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2 years ago

Determine if the two triangles are congruent. If they are, state how you know.

Mathematics

1 answer:

Elza [17]2 years ago

6 0

Angle-side-angle is a rule used to prove whether a given set of triangles are congruent. The ASA rule states that: If two angles and the included side of one triangle are equal to two angles and included side of another triangle, then the triangles are congruent

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Find an equivalent system of equations for the following system: 3x + 3y = 0 −4x + 4y = −8

Rama09 [41]

Answer:

Answer:

3x + 3y = 0

7x - y = 8

Step-by-step explanation:

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3 years ago

A rectangle is 4xcm wide and 2cm long what do you notice

deff fn [24]

The width of the rectangle is twice the length of the rectangle

<h3>How to compare the dimensions of the rectangle?</h3>

The given parameters are:

Width = 4 cm

Length = 2 cm

Express 4 cm as 2 * 2 cm

Width = 2 * 2 cm

Substitute Length = 2 cm in Width = 2 * 2 cm

Width = 2 * Length

This means that the width of the rectangle is twice the length of the rectangle

Hence, the true statement is that the width of the rectangle is twice the length of the rectangle

Read more about rectangles at:

brainly.com/question/25292087

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1 year ago

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3 years ago

Suppose that the function g is defined, for all real numbers, as follows.

svetoff [14.1K]

Answer:

a) g(-2) = 0

b) g(-1) =1

c) g(4) = 2

Step-by-step explanation:

Given data

$g(x) = \frac{-1}{4x+1} if x < -2$

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

$g(x) = 2 if x >2$

Step( i ):-

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

put x = -2

$g(-2) = -(-2+1)^{2} +1 = -(-1)^{2}+1 = -1+1 =0$

g(-2) = 0

Step(ii):-

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

Put x = -1

$g(-1) = -(-1+1)^{2} +1 = -(0)^{2}+1 = -0+1 =1$

g(-1) =1

Step(iii):-

$g(x) = 2 if x >2$

g(4) = 2

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3 years ago

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Answer:

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Step-by-step explanation:

Go to school, sit down, and you will come to find the answer

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3 years ago