Find the 83rd term of the arithmetic sequence -23, -26, -29, I need help
2 answers:
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Answer:
f(x+2)=3x+10
Explanation:
f(x+2) means replace all the xs with (x+2)
f(x)=3x+4
f(x+2)=3(x+2)+4
Now simplify
f(x+2)=3x+6+4
f(x+2)=3x+10
f(x+2)=3x+10
Explanation:
f(x+2) means replace all the xs with (x+2)
f(x)=3x+4
f(x+2)=3(x+2)+4
Now simplify
f(x+2)=3x+6+4
f(x+2)=3x+10
Answer:
AB = 83
Step-by-step explanation:
The mid-point of any segment divides the segment into two equal parts
∵ B is the midpoint of segment AC
→ That means B divides AC into two equal segments AB and BC
∴ AB = BC
∵ AB = 12x + 11
∵ BC = 14x - 1
→ Equate them
∴ 14x - 1 = 12x + 11
→ Subtract 12x from both sides
∵ 14x - 12x - 1 = 12x - 12x + 11
∴ 2x - 1 = 11
→ Add 1 to both sides
∵ 2x - 1 + 1 = 11 + 1
∴ 2x = 12
→ Divide both sides by 2
∵
∴ x = 6
→ To find AB substitute x by 6 in its expression
∵ ab = 12x + 11
∵ x = 6
∴ AB = 12(6) + 11
∴ AB = 72 + 11
∴ AB = 83