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tensa zangetsu [6.8K]
3 years ago
11

IMPORTANT PLEASE HELP

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

a + c = 80

a = 2c - 8

Step-by-step explanation:

Topic: Algebra

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Write the function in standard form <br><br> f(x) = -5 (x-7)^2 +11
Lapatulllka [165]

3x+1=1 because it is a hard problem to solve just ask your teacher

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3 years ago
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Need help solving for X
Stels [109]
I hope this helps you



x=108/6


x=18

4 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
4(v – 6) + 5 = 4v - 19
erik [133]

Answer:

0

Step-by-step explanation:

is it helpful or not,?

8 0
3 years ago
Ill give you a brainliest if you get it right
lesantik [10]
A&d i think.. but basically the equation needs to be modeled where the answer will be a 14° difference
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