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kondaur [170]
3 years ago
13

Absolute Value.

Mathematics
1 answer:
Zina [86]3 years ago
7 0

The answer is B 5+-3--2 =4

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Put the following equation in slope-intercept form: 2x+4y=12
guajiro [1.7K]
Y=-1/2x+3 is the slope intercept form.
4 0
3 years ago
Explain pls and thanks
murzikaleks [220]

Starting more simply, if we wanted to know how many students like pink in general, that's 68/100. We could do that for each single category and the fractions would add together to equal 1. Now say we wanted to know something about that 68/100 people. That 68 is our new 100%, or another way of looking at it is if we take however many people like pink and don't like black and those that do like black, they will equal 68/68.

The number of people that like pink but don't like black is 41/68 and those that like pink and black are 27/68. 27+41=68 For the question of your problem it is asking about those that do not like pink which you can tell from the table or use from my saying 68/100 like pink is 32. Now you can split that into those that do or don't like black, and the two results will equal 32/32.

7 0
3 years ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
Which equation represents a line that passes through (2, –left-parenthesis 2, negative StartFraction one-half EndFraction right-
kompoz [17]

Answer:

16

Step-by-step explanation:

correct on Edg

7 0
2 years ago
Last option is none of the above
BigorU [14]

Answer:

A and B

Step-by-step explanation:

When rotating a point (or any shape around a certain point), none of the diameters of the shape will change. So for example, with this circle, when you rotate it around a point, the radius and circumference will not change because it has just rotated. It wont be on the x-axis though because point P is not on the x-axis an it is being rotated 180 degrees about point P. Just know that when you are rotating, nothing about the shape changes, all angles or measurements will be the same, it is just moving to a different place.

Hope this helped ^-^

7 0
3 years ago
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