The formula you can use for the withdrawals is that of an annuity. You have interest adding to the balance at the same time withdrawals are reducing the balance.
The formula I remember for annuities is
.. A = Pi/(1 -(1 +i)^-n) . . . . . i is the interest for each of the n intervals; A is the withdrawal, P is the initial balance.
This formula works when the withdrawal is at the end of the interval. To find the principal amount required at the time of the first withdrawal, we will compute for 3 withdrawals and then add the 7500 amount of the first withdrawal.
.. 7500 = P*.036/(1 -1.036^-3)
.. 7500 = P*0.357616
.. 7500/0.0347616 = P = 20,972.20
so the college fund balance in 4 years needs to be
.. 20,972.20 +7,500 = 28,472.20
Since the last payment P into the college fund earns interest, its value at the time of the first withdrawal is P*1.036. Each deposit before that earns a year's interest, so the balance in the fund after 4 deposits is
.. B = P*1.036*(1.036^4 -1)/(1.036 -1)
We want this balance to be the above amount, so the deposit (P) is
.. 28,472.20*0.036/(1.036*(1.036^4 -1)) = 6510.62
You must make 4 annual deposits of $6,510.62 starting now.
Answer:
The area is equal to 30 + 24 + 9 = 63
ANSWER:
35
DID YOU COPY MY ANSWER THAT IS CORRECT
Answer:
15-4(sqrt39)/40
Step-by-step explanation:
just did it on edge
2x+ y = -4 5x + 3y = -6
y= -4 -2x
substitute y=-4-2x into 5x+3y=-6
5x + 3(-4-2x) = -6
5x -12 -6x =-6
-x=6
x=-6
sub x=-6 into 2x+y=-4
-12 + y = -4
y=8
x=-6 and y=8
