Answer:
12√2.
Step-by-step explanation:
You can do this by the Pythagoras theorem:
20^2 = x^2 + (4sqrt7)^2 where x is the distance required.
x^2 = 20^2 - (4sqrt7)^2
= 400 - 112
= 288
x = √288
= √144 *√2
= 12√2.
Answer:
Length =24m and width = 21m
Step-by-step explanation:
Given,
Area of rectangle, A = 504 m^2
Perimeter of rectangle, P = 90 m
Since we know, A = Length * width and P = 2(Length + width)
So, A = L * w
=> 504 = L*w ------------------(1)
And P = 2(L + w)
=> 90 =2( L + w) ----------------(2)
Plug L =504/w in equation 2
i.e. 90 = 2( 504/w + w)
or 45 = 504/w + w
or 45 = (504 + w^2 ) / w
or 45w = 504 + w^2
or w^2 - 45w + 504 = 0
On solving above quadratic equation we get:
w = 21 or 24
So we take width , w= 21 meter
Then length will be, L =504/21 =24 meter
Hence length and width of rectangle are 24m and 21m respectively.
Answer:
Step-by-step explanation:
Given that you choose at random a real number X from the interval [2, 10].
a) Since this is a contnuous interval with all number in between equally likely
E = probability for choosing a real number is U(2,10)
pdf of E is 
b) P(X>5) = 
For
P(X<5 or x>7) = 1-P(5<x<7)
= 
Answer:
0
Step-by-step explanation:
