<u>Pros :- Social media:</u>
- Normally using is good up to one stage where information of organization is not shared through social media.  
- News day social media is used to share the common information with validation. 
- In social media access by end user out of office hours.
<u>Cons:- Social media:</u>
- In an organization an important files or document or media is shared then it is danger.
- Mostly end user access the social media in office hours then growth of organization is will be affected.
- Since end user using the organization internet then cost of internet will rise.
 
        
             
        
        
        
False
Tier 1 ISPs exchanges traffic with other tier 1 internet traffic
providers and are the backbone of the internet. They do not provide traffic to
end users but provide internet to other ISPs. Tier 3 is the last mile provider who delivers
internet access to homes and businesses. 
 
        
             
        
        
        
Answer: Accenture is developing a tool to help businesses detect gender, racial and ethnic bias in artificial intelligence software. 5 It lets users define the data fields they consider sensitive—such as race, gender or age—and then see the extent to which these factors are correlated with other data fields.
Explanation:
 
        
             
        
        
        
I'm hoping this hasn't already been answered, am sure I saw a similar post. 
12.Noise 
13. Wow.... that is worded so awkwardly. Am assuming it's terminator, because it's the only option there that is a physical device.  
14.Terminator
 
        
             
        
        
        
Answer:
#include<iostream>
#include <vector>
#include <list>
using namespace std;
int main(){
int a[10]={0,1,2,3, 4, 5, 6, 7, 8, 9 };
std::vector<int> v (&a[0],&a[0]+10);
std::list<int> l (&a[0],&a[0]+10);
int b[10];
for(int i=0;i<10;i++){
b[i]=a[i];
}
std::vector<int> v2(v);
std::list<int> l2(l);
for(int i=0;i<10;i++){
b[i]+=2;
}
for(int i=0;i<10;i++){
v2[i]+=3;
}
for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)
*it=*it+5;
cout<<"Each containers value are: "<<endl;
cout<<"1st array: "<<endl;
for(int i=0;i<10;i++){
cout<<a[i]<<" ";
}
cout<<"\n 1st vector: \n";
for(int i=0;i<10;i++){
cout<<v[i]<<" ";
}
cout<<"\n 1st List is:\n";
for (std::list<int>::iterator it = l.begin(); it != l.end(); it++)
cout << *it << ' ';
cout<<"\n 2nd array: "<<endl;
for(int i=0;i<10;i++){
cout<<b[i]<<" ";
}
cout<<"\n 2nd vector:\n";
for(int i=0;i<10;i++){
cout<<v2[i]<<" ";
}
cout<<"\n 2nd list:\n";
for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)
cout << *it << ' ';  
return 0;
}
Explanation:
- Initialize an array, a vector and a list of type integer
.
- Create a 2nd array, vector, and list as a copy of the first array, vector, and list.
- Increase the value of each element in the array by 2
, vector by 3 and list by 5.
- Finally display the relevant results.