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3 years ago

Reflect the image over the y-axis and then translate 8 units down. What are the coordinates for C’?

Mathematics

1 answer:

irakobra [83]3 years ago

3 0

Answer:

(-7, -7)

Step-by-step explanation:

1. Let's ONLY focus on point C.

2. The algebraic rule for reflecting across the y-axis is (x, y) -> (-x, y).

Since point C is on the coordinate (7,1), when reflecting it across the y-axis, it's going to turn into (-7,1).

3. The algebraic rule for translating 8 units down is (x, y) -> (x, y - 8).

Since C is on (-7,1), when we translate it 8 units down, we'll get C' as (-7, -7)

Therefore, the coordinates for C' are (-7, -7).

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Answer:

75 kilómetros por hora creo no estoy muy seguro

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2 years ago

©MP.4 Model with Math

evablogger [386]

Answer:

The drawings are in the picture attached and the explanations are below.

Question 1.

Equation: w = 10 × 8 lb

Solution: x = 80 lb

Question 2:

Equation: d = 10×8 lb - 8 lb
Solution: d = 72 lb

Explanation:

Question 1:

Statement 1: Mary was born, she weighet 8 lbs
Statement 2: When she was 10 years old weighed 10 times as much

w = 10 × 8 lbs = 80 lbs

Explanation of the drawing:

Each cell represents 8 lbs, which was the weight when she was born. There are 10 cells, representing that the amount 8 lbs is repeated 10 times.

Then, the multiplication is represented an abbreviated sum:

8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 = 10 × 8 = 80

Question 2:

Statement: find the difference, d, between Mary's weight when she was 10 years old and when she was born.

d = 80 lbs - 8 lbs = 72 lbs

↑ ↑ ↑ ↑

difference 10 years old born solution

Explanation of the drawing:

When you subtract one cell (8 lb) from ten cells (10 × 8 = 80 lb), you obtain nine cells ( 9 × 8 lb = 72 lb).

6 0

3 years ago

Free branliest to first one who answers!

pentagon [3]

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3 years ago

Read 2 more answers

Compare 4 x 10^6 and 2 x 10^7.

marishachu [46]

Answer:

C. $2\times 10^7$ is 5 times larger than $4\times 10^6$

Step-by-step explanation:

We want to compare $4\times 10^6$ and $2\times 10^7$ .

In order to determine how many times

$2\times 10^7$

is larger than

$4\times 10^6$ ,

we need to divide $2\times 10^7$ by $4\times 10^6$ to obtain;

$\frac{2\times 10^7}{4\times 10^6} =\frac{10}{2} =5$

Therefore we can see that;

$2\times 10^7$ is 5 times larger than $4\times 10^6$

The correct answer is C.

6 0

3 years ago

Find, correct to the nearest degree, the three angles of the triangle with the given ven

Scrat [10]

9514 1404 393

Answer:

∠CAB = 86°

∠ABC = 43°

∠BCA = 51°

Step-by-step explanation:

This can be done a couple of different ways (as with most math problems). We can use the distance formula to find the side lengths, then the law of cosines to find the angles. Or, we could use the dot product. In the end, the math is about the same.

The lengths of the sides are given by the distance formula.

AB² = (4-1)² +(-3-0)² +(0-(-1)) = 16 +9 +1 = 26

BC² = (1-4)² +(2-(-3))³ +(3-0)² = 9 +25 +9 = 43

CA² = (1-1)² +(0-2)² +(-1-3)² = 4 +16 = 20

From the law of cosines, ...

∠A = arccos((AB² +CA² -BC²)/(2·AB·CA)) = arccos((26 +20 -43)/(2√(26·20)))

∠A = arccos(3/(4√130)) ≈ 86°

∠B = arccos((AB² +BC² -AC²)/(2·AB·BC)) = arccos((26 +43 -20)/(2√(26·43)))

∠B = arccos(49/(2√1118)) ≈ 43°

∠C = arccos((BC² +CA² -AB²)/(2·BC·CA)) = arccos((43 +20 -26)/(2√(43·20)))

∠C = arccos(37/(4√215)) ≈ 51°

The three angles are ...

∠CAB = 86°

∠ABC = 43°

∠BCA = 51°

_____

Additional comment

This sort of repetitive arithmetic is nicely done by a spreadsheet.

6 0

3 years ago