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Marysya12 [62]
3 years ago
7

Polynomial standard form for the square root of 7n^4

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0

Step-by-step explanation:

Given

\sqrt{7n^4}

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

ax^2+bx+c

Rewrite 7n^4 as  \left(n^2\right)^2\cdot 7

Rewrite  n^4  as \left(n^2\right)^2

so

\sqrt{7\left(n^2\right)^2}

Reorder  7 and \left(n^2\right)^2

\sqrt{\left(n^2\right)^2\cdot 7}

Pull terms out from under the radical.

\:n^2\sqrt{7}

So writing in standard form

\:n^2\sqrt{7}                  

  • Degree: 2                             (Highest power of variable n)
  • Leading coefficient: \sqrt{7}  
  • Type: Monomial
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Answer:

37

Step-by-step explanation:

The first thing is to calculate critical z factor

the alpha and the critical z score for a confidence level of 90% is calculated as follows:

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critical z factor for two sided alpha of .05 is calculated as follows:

critical z factor = z factor for (1 - .05) = z factor for (.95) which through the attached graph becomes:

critical z factor = 2.58

Now we have the following formula:

ME = z * (sd / sqrt (N) ^ (1/2))

where ME is the margin of error and is equal to 6, sd is the standard deviation which is 14 and the value of z is 2.58

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solving for N we have:

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Express each fraction as a percent 7/20
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Answer:

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Step-by-step explanation:

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