Question

Polynomial standard form for the square root of 7n^4

Answer 1

Step-by-step explanation:

Given

$\sqrt{7n^4}$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$ax^2+bx+c$

Rewrite $7n^4$ as  $\left(n^2\right)^2\cdot 7$

Rewrite  $n^4$  as $\left(n^2\right)^2$

so

$\sqrt{7\left(n^2\right)^2}$

Reorder  7 and $\left(n^2\right)^2$

$\sqrt{\left(n^2\right)^2\cdot 7}$

Pull terms out from under the radical.

$\:n^2\sqrt{7}$

So writing in standard form

$\:n^2\sqrt{7}$                  

• Degree: 2                             (Highest power of variable n)

• Leading coefficient: $\sqrt{7}$  

• Type: Monomial