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valina [46]
3 years ago
6

Could Anyone Help Me Get 3 More Brainliest So I Can Go Past Ambitious Because I Have 699 Points But Only 2 Brainliest. All Help

Worthy <3
Mathematics
1 answer:
Sliva [168]3 years ago
7 0

Answer:

No, sorry. I have 57 brainliest and I worked hard for it, i'm sure you could too.

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photoshop1234 [79]
The answer is twelve and you can thank me later
6 0
3 years ago
Solve for q 2/3=-1/3q
tensa zangetsu [6.8K]
Q in (-oo:+oo)

2/3 = (1/3)*q // - (1/3)*q
                                                                  
2/3-((1/3)*q) = 0                                             
                                                                       ddddddddd
                                                                       d              d      
                                                                       d              d
(-1/3)*q+2/3 = 0                                              d              d
                                                                       d              d
2/3-1/3*q = 0 // - 2/3                                       d              d
                                                                       d              d
-1/3*q = -2/3 // : -1/3                                       d              d
                                                                       d              d
q = -2/3/(-1/3)                                    ddddddd               dddddddd     
                                                     dd                                               dd
q = 2                                            dd                                                 dd
                                                    dd                   dddd                      dd
q = 2                                              dddddddddd          dddddddddddd
6 0
3 years ago
Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5
MAXImum [283]

Answer:

<h2>7</h2>

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

5 0
3 years ago
If a = 5 and b = 2 and c= 3, explain why a + b/c -3 cannot be evaluated
avanturin [10]
A+b is 5+2 which equals 7
c=3 but 7 cannot be divided by 3.
which would be why this cannot be evaluated
3 0
3 years ago
Read 2 more answers
Oliver and Peter had the same length of string. Oliver used 3/4 of his string to tie a bundle of newspaper. Peter used 6/8 of hi
solmaris [256]

Answer:

Yes they did.

Step-by-step explanation:

So you have the fraction 3/4 and 6/8. If you divide the fraction 6/8 by 2 you will get 3/4 since 6/8 is an unsimplifed form of 3/4.

7 0
3 years ago
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