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insens350 [35]
3 years ago
15

Use a division ladder to find the GCF of 34 and 60. A4 B3 C1 D2

Mathematics
1 answer:
Sloan [31]3 years ago
5 0

Answer:

D.2


Step-by-step explanation:

First, you need to divide 34 and 60 by A.4, when you divide that you see that 4 dose not go in to 34 evenly and go"s in to 60 evenly, so this is incorect.


Now we will divide 34 and 60 by B.3, when you divide, you see that 3 dose not go into 34 evenly and go"s in to 60 evenly, so this is also incorect.


Then we divide 34 and 60 by C.1, when we divide this one you find that 1 go"s in to 34 evenly and 60 evenly, so this is a posible answer.


finally we divide 34 and 60 by D.2, when we do this we find that 2 go"s in to 34 evenly and 60 evenly, so this is also a posible answer.


All though C. and D. both go in to 34 evenly and 60 evenly, we are looking for the GCF (Greatest Common Factor). So the biggest number of C.1 and D.2, is D.2


So the answer is D.2.


Hoped this helped, Have a grate day!

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Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
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  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

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Divide each side by .60 to get the variable by itself. .75/.60= 1.25.


Hope this helped!!! :)

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