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I am Lyosha [343]
2 years ago
7

Mrs. Cooper has $20 can she buy a museum tickets for 10 year old daughter a ticket for a self and a book that cost 3.99? Explain

: child price: $5.75 Adult price: $11.25
Mathematics
1 answer:
Sladkaya [172]2 years ago
7 0

No, because then she would have to pay 21 dollars  as a total and she only has 20.

Add adult plus Child,

5.75 + 11.25 = 17

add that to the book's price,

17+3.99= 2.99

it will exceed the budget by 99 cents.

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docker41 [41]

Answer: D (bottom option)

Not Congruent

Step-by-step explanation:

Assuming the trapezoids are to scale, they are not the same shape. This means that they could not be congruent even if they were centered on top of each other.

3 0
1 year ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

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3 years ago
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