Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
Answer:
Hey there!
When z=48, y=6.
z is 8 times as much as y.
11 part 1: z=8y
11 part 2: I'm going to attach a graph I created at the bottom of this answer :)
Let me know if this helps :)
Answer:
23
Step-by-step explanation:
if y=8 then you plug it inti the equation
2(8)+7
16+7=23
Answer: no real solution
Thus, the function has no x- intercept
Step-by-step explanation:
In a triangle, the midline joining the midpoints of two sides is parallel to the third side and half as long
2(5x+2) = 3x + 32
10x + 4 = 3x + 32
10x - 3x = 32 - 4
7x = 28
x = 28/7
x = 4
The length of the midsegment = 5x+2 = 5·4 + 2 = 22