There are four banana, one strawberry and one water-melon smoothies, six in all.
Assuming all smoothies are identical when we pick, then the probability of picking a particular one is one divided by the total number (of smoothies).
Since there are four banana smoothies, the probability of picking a banana smoothie is four divided by six, or four-over-six, or two-thirds.
There are now five smoothies remaining, of which three are banana. Therefore the probability of picking another banana is three-over-five, or three fifths.
The final probability is the product of the individual (we call it a two-step experiment), or two-third multiplied by three-fifths, equal to two-fifths, or forty percent.
Recall that if the first banana smoothie had been put back in the batch, the probability would come out different.
Answer:
r
Step-by-step explanation:
10r - 9r = r
against wind the speed = x-y
distance traveled = 2460
2460/x-y= 6
6x-6y= 2460
x-y=410...........1
..
with wind speed = x+y
distance is same 2460
2460/x+y=5
5x+5y=2460
x+y=492............2
..
Add equation 1 & 2
x-y+x+y=410+492
2x=902
x= 451 mph speed of plane in still air.
..
Plug the value of x in equation 1
451-y=410
y=451-410
y=40 mph the speed of wind
.
Your feed back about the solution is very important in improvement.
Assume the original mass,
a=100, then we know
p(t)=0.6*100=60,
h=100,
Substitute into equation and solve for t.
60=100*(1/2)^(t/100)
divide by 100
0.6=(1/2)^(t/100)
take log on both sides
log(0.6)=(t/100)log(1/2)
divide each side by log(1/2)
t/100=log(0.6)/log(0.5)
t=100log(0.6)/log(0.5)
=100(-0.5108)/(-0.6931)
=73.70 days, approximately