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Elza [17]
3 years ago
8

Need help ...what is the slope line passing through (-5,-3) and (-7,-12)

Mathematics
1 answer:
Mumz [18]3 years ago
5 0

This should show you the answer!

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Pleaseee helpppTyler left his house and drove to the store. He stopped and went inside. From there, he drove in the same directi
yulyashka [42]

Answer:

4 minutes

Hope this helps!!! :)

7 0
3 years ago
If g (x)= x+1/x-2 and h(x) =4-c, what is the value of (g•h)(-3)?
Kay [80]

Answer:

Step-by-step explanation:

g(h(-3)) = g(7)

As h(x)= 4-x so h(-3) = 4+3=7

(g•h)(-3)= g(7) = 7+1/7-2= 8/5

8 0
3 years ago
Read 2 more answers
What condition on the probability distribution is necessary and sufficient in order that a limiting distribution exist, and what
Sholpan [36]

Answer:

The Markov chain is a description of the sequence of possible events in which the probability of an event depends only on the state attained in a previous separate event.

Step-by-step explanation:

The relation described by the Markov chain satisfies the following conditions:

1. All states communicate with themselves, that is P₁₁⁰ = 1 ≥ 0

2. There must be symmetry: if i←→j, then j ←→i

3. There must be transitivity. That is if i ←→k and k←→j, then i←→j

The conditions above imply that the communication is an example of an equivalence relation, meaning that it shares the properties with the more familiar relation, that is

i = i , if i = j ,then j = i etc

5 0
4 years ago
Can someone help me with this question
trapecia [35]

the answer is c hope that helps and have a nice day

7 0
4 years ago
Please help me with the following (1-5)
Ivanshal [37]

1. \: 405352  \: cm = 4.05352 \times  {10}^{5}  \: cm

___o___o___

2. 7.6352 x 10-3 kg ( This is scientific notation) [ If you want —> Standard notation]

7.6352 x 10^ -3 kg = 0.0076352 kg

__o_o___

3. \:  \: 3.1 \times 10 ^{4} mm + 4.87 \times  {10}^{5}  \: mm \\ 0.31\times 10 ^{4} mm + 4.87 \times  {10}^{5}  \: mm \\  = 5.18 \times  {10}^{5}  \: mm

____o___o___

4. \:  \: (4.8 \times  {10}^{5}  \: km) \times (2.0 \times  {10}^{3} \: km ) \\  = 9.6 \times  {10}^{8}  \: km

____o____o____

5.(3.3 \times{10}^{ - 4}\: ml)\div(1.1 \times  {10}^{ - 6}\: ml)  \\  \\  \frac{3.3 \times  {10}^{ - 4}  \: ml}{1.1 \times  {10}^{ - 6}  \: ml}  = \frac{33 \times  {10}^{ - 4}  \: ml}{11 \times  {10}^{ - 6}  \: ml}   \\  \\  =  \frac{33 \times  {10}^{ - 4 + 6} }{11} ml \\  \\  = 3 \times  {10}^{2}  \: ml

I hope I helped you^_^

6 0
3 years ago
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