Question

At maximum speed, an airplane travels

Answer 1

against wind the speed = x-y

distance traveled = 2460

2460/x-y= 6

6x-6y= 2460

x-y=410...........1

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with wind speed = x+y

distance is same 2460

2460/x+y=5

5x+5y=2460

x+y=492............2

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Add equation 1 & 2

x-y+x+y=410+492

2x=902

x= 451 mph speed of plane in still air.

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Plug the value of x in equation 1

451-y=410

y=451-410

y=40 mph the speed of wind

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