Answer:
B.carries and allows expression of a foreign gene of interest.
Explanation:
Plasmids are the low molecular weight extrachromosomal DNA molecules that are able to replicate themselves independent of chromosomal DNA due to the presence of "ori" (origin of replication).
Plasmids serve as vectors in recombinant DNA technology as some of their genes can be replaced with the gene of interest to create recombinant plasmids.
The restriction enzymes that create the sticky ends and DNA ligases facilitate the insertion of the foreign gene into the plasmids.
The host cells are made competent to take up the recombinant plasmids. Once inside the host cell, the recombinant plasmids replicate themselves and express the gene of interest that they carry.
Answer:
mass₁=100.0g
time₁=2.70 days
mass₂=x
time₂=8.10 days
8.10/2.70 = 3
100/2 = 50/2 = 25/2 = 12.5 g
x=12.5 g
<span>The provider's success claims seem too good to be true.</span>
<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>
In biology the word <em>bio</em><em> </em><em>catylysts</em><em> </em>describes the word enzymes . Bio catylysts are nothing but enzymes which alter the rate of reaction . For ex - Pepsinogen , which is produced in the stomach of humans activated by HCl from a proenzyme called trypsin . It works in acidic medium and converts proteins into peptides and protons . Likewise there is another enzyme called Salivary amylase which is present in the saliva of humans converts starch into maltose . There is another enzyme called lipase which converts fats into fatty acids and glycerol .
Answer:
3/16
Explanation:
Given,
Black coat color is dominant over brown coat color.
Long mane is dominant over short mane.
BBLL X bbll =
F1: BbLl = Entire progeny has black color and long mane
BbLl progeny will produce BL, Bl, bL and bl gametes. When they interbreed, the resultant F2 progeny will be in 9:3:3:1 dihybrid ratio. Hence in F2,
BBLL : BbLL : bbLl : bbll = 9 : 3 : 3 : 1
3/16 progeny will have bbLl genotype hence 3/16 progeny will have brown, long mane.
