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Zanzabum
3 years ago
15

Round 681,858 to the nearest hundred thousand

Mathematics
2 answers:
jeka943 years ago
6 0

Answer:

700,000

Step-by-step explanation:

So really, in this question, all you care about is the 10,000ths place

The 10,000ths place in this number is 8. Since 8 is greater that four, round up to 700,000

Marta_Voda [28]3 years ago
6 0

Answer:

700,000

Step-by-step explanation:

Round off all the numbers after the first number

If rounded off and the number closest to the first no is 5 and above, it automatically approximates the next number to its left.

Example: 681,858

The last no is 8, it therfeore approximates 5, thereby changing it to a 6

After being changed to a 6, it approximates the next no to its left, 8, turning it into a 9, nine approximates 1, turns it to a 2, two can't approximate, it's below 5, move on to 8, eight approximates 6 turning it to a 7, that's how I got my 700,000.

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Se tiene la sucesión 3, 8, 13, 18, 23 … ¿Cuáles son los siguientes dos términos y cuál es la regla general?
V125BC [204]

Respuesta:

28; 33

A (n) = 5n - 2

Explicación paso a paso:

A partir de los datos dados, 3, 8, 13, 18, 23…, podemos ver que cada valor sucesivo de la serie aumenta en 5;

Por lo tanto, los siguientes dos términos de la serie deberían ser:

23 + 5 = 28

28 + 5 = 33

La serie es una progresión aritmética:

Recuerde la fórmula general:

A (norte) = a + (norte - 1) d

Donde, a = Primer término = 3; d = diferencia común = 5

n = enésimo término

A (n) = 3 + (n-1) 5

A (n) = 3 + 5n - 5

A (n) = 5n - 2

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3 years ago
Which equation can be used to find the solution of (1/4)^y+1=64?
Ne4ueva [31]

Answer:

−y−1=3

Step-by-step explanation:

Which equation can be used to find the solution of (1/4)^y+1=64?

This can be solved by power of indices

(1/4)^(y+1)=64

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Hence, the equation that can be used to find the solution of (1/4)^y+1=64 is

−y−1=3

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Step-by-step explanation:

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