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elixir [45]
3 years ago
5

What is the inverse of the function g(x)=-2/3x-5

Mathematics
2 answers:
professor190 [17]3 years ago
6 0

Answer:

f^-^1(x) = -\frac{3}{2}x  - \frac{15}{2}

Step-by-step explanation:

<u>Step 1:  Set x to y and y to x</u>

<u />y = -2/3x - 5

x = -2/3y - 5

<u>Step 2:  Solve for y</u>

<u />x + 5 = -2/3y - 5 + 5

x + 5 = -2/3y

-3/2(x + 5) = -2/3y * -3/2

-3/2x - 15/2 = y

<u>Step 3:  Make new equation</u>

<u />f^-^1(x) = -\frac{3}{2}x  - \frac{15}{2}

Answer:  f^-^1(x) = -\frac{3}{2}x  - \frac{15}{2}

Margaret [11]3 years ago
5 0

Answer:

-3/2x -15/2

Step-by-step explanation:

g(x)=-2/3x-5

y = -2/3x -5

Exchange x and y

x = -2/3y -5

Solve for y

Add 5 to each side

x+5 = -2/3y-5+5

x+5 = -2/3y

Multiply each side by -3/2

-3/2(x+5) =-3/2*-2/3y

-3/2x -15/2 =y

The inverse is -3/2x -15/2

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