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Aliun [14]
3 years ago
11

Point z is the incenter of δsrt. What is mztb? 24° 31° 35° 62°.

SAT
1 answer:
elena-s [515]3 years ago
8 0

Answer:

The line from an incenter to a vertex bisects the angle that is produced there. You probably notice this in angle ASB and angle ARC. Therefore, angle ZTB is going to be equal to half of the angle measure of BTC. We can do the following:

24+24+35+35+x+x=180 (x represents the two angles in angle BTC when they are bisected)

simplifies to

2x+118=180

Solving for x, we get that x=31.

So angle ZTB=31.

Explanation:

hope this hlpsmark me brainleist

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Based on the calculations, we have the following:

  1. The area of the sheet of paper is 96 square inches.
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<u>Given the following data:</u>

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Mathematically, the area of the paper is given by this formula:

Area = length \times breadth\\\\Area = 12 \times 8

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Therefore, the combined area of the triangle cutouts is given by:

A_2= (2 \times \frac{1}{2} \times 2 \times 9) + 2 \times \frac{1}{2} \times 3 \times 6\\\\A_2=18+18\\\\A_2=36\;in^2

<h3>The area of the parallelogram.</h3>

This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:

P = A_p -A_2\\\\P=96-36

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<h3>The altitude of the parallelogram.</h3>

P = base \times altitude\\\\Altitude =\frac{P}{base} \\\\Altitude =\frac{60}{9.22}

Altitude = 6.51 square inches.

Read more on parallelogram here: brainly.com/question/4459854

<u>Complete Question:</u>

A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.

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