All categories

3 years ago

26: = α : 8 18:x= x:8

Mathematics

1 answer:

nikitadnepr [17]3 years ago

5 0

Answer:

,=your head

Step-by-step explanation:

thanks for the points bye bye

You might be interested in

Solve the inequality. Graph the solution.<br> 7z< -28

Zepler [3.9K]

Answer: The answer is -9

Step-by-step explanation:

7z<-28= -9

Because we take the -28 and add 19 because that's the common denominator and we come up with -9

6 0

3 years ago

Which expression represents a number that is four times as large as the sum of 8 and 160?

DedPeter [7]

ANSWER: x = 4 ( 8 + 160 )

STEP BY STEP:

Let's start by getting a variable to represent the number. Let's use x. ⇩

x=

Now we know that there is a sum of 8 and 160. Let's add them to each other ⇩

x= 8 + 160

Now we know that this will be multiplied. Let's put parentheses around the addition to symbolize this.

X= (8 + 160)

Finally multiply this by four, making your equation

x= 4 (8 + 160)

I don't know the options but from looking at the problem I'm assuming the answer is
x = 4 ( 8 + 160 )

8 0

3 years ago

The two figures are similar. Find the ratios

elena-14-01-66 [18.8K]

Answer:

1/5 to 1/5

Step-by-step explanation:

7 0

3 years ago

I need help with the questions underlined !! Please help !!! ASAP

dybincka [34]

This is social studies put it i. Math don’t mean to be mean

6 0

3 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

4 years ago

Read 2 more answers