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Answer:
the answer in words is eighteen thousand five hundred and eighty two Rand and seven cents
Answer:
Factor this polynomial:
F(x)=x^3-x^2-4x+4
Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).
The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at
x = 1, x = 2 and x = -2. This means that
x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)
A = 1, as you can see from equation the coefficient of x^3 on both sides.
Typo:
The rational roots can be
+/-1, +/-2 and +/-4
Step-by-step explanation:
Answer:
42 = <em>l</em>
21 = <em>w</em>
Step-by-step explanation:
{l = 2<em>w</em>
{126 = 2<em>w</em> + 2<em>l</em>
126 = 2<em>w</em> + 2[2<em>w</em>]
126 = 2<em>w</em> + 4<em>w</em>
126 = 6<em>w</em>
21 = w [Plug this back into both equations to get the length of 42]; 42 = <em>l</em>
I am joyous to assist you anytime.
