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saw5 [17]
3 years ago
11

Classify the following triangle. Check all that apply.

Mathematics
2 answers:
UkoKoshka [18]3 years ago
5 0

Answer:

F.Scalene

Step-by-step explanation:

every angles and sides of scalene triangle is not equal

Lelechka [254]3 years ago
4 0
The correct answer is C Acute, and F Scalene.
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What is the value of the expression when a = 6, b = 4, and c = 8?
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a the answer is a

Step-by-step explanation:

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Divide 405 in to the ratio 3:12<br> give answer in the form ... and ...
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Answer:

81:324

Step-by-step explanation:

3+12=15

405 div 15 =27

3 times 27 = 81

12 times 27 = 324

81:324

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a sphere and a cone have the same volume. each figure has a radius of 3 inches. what is the height of cone
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(4/3) Pi r^3 = (1/3) Pi r^2 h
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There are 20 rows of seats on the concert hall:25 seats are in the 1st row
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Answer:

20x25=500 10x25+10×25=500

7 0
3 years ago
A financial talk show host claims to have a 55.3 % success rate in his investment recommendations. You collect some data over th
baherus [9]

Answer:

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

Step-by-step explanation:

For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.553, n = 10

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:

This is

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.553)^{0}.(0.447)^{10} = 0.0003

P(X = 1) = C_{10,1}.(0.553)^{1}.(0.447)^{9} = 0.0039

P(X = 2) = C_{10,2}.(0.553)^{2}.(0.447)^{8} = 0.0219

P(X = 3) = C_{10,3}.(0.553)^{3}.(0.447)^{7} = 0.0724

P(X = 4) = C_{10,4}.(0.553)^{4}.(0.447)^{6} = 0.1567

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0003 + 0.0039 + 0.0219 + 0.0724 + 0.1567 = 0.2552

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

3 0
3 years ago
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