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Afina-wow [57]
4 years ago
8

To insert an endnote, which steps should you follow?

Computers and Technology
1 answer:
Evgesh-ka [11]4 years ago
6 0
<span>To insert an endnote, you should follow he following steps:
A.Place the cursor in the document where you want the note reference mark to appear, select Insert Endnote command from the Reference tab in the Footnotes group.
Correct answer: A
</span><span>This way a reference mark would be added in the text and the endnote will be added at the end of the document.</span>
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What is the channel capacity for a teleprinter channel with a 300 Hz bandwidth and a signal-to-noise ratio of 30dB, where the no
wolverine [178]

Answer:

The answer is 2988 bits per seconds

Explanation:

Solution

Given that:

Bandwidth (B) = 300Hz

Signal to noise ratio (SNR) = 30dB

Now let C = channel capacity

Using  Deubel formula we have the following:

SNR db = 10* log (SNR)

30 =10* log (SNR)

So,

SNR =log^⁻1 (3)

SNR = (10)^3

SNR = 1000

Thus SNR =1000

Now

Applying the Shannon's equation

C = B * log₂ ( 1 + SNR)

C = 300 * log₂ ( 1 + 1000)

C = 300 * log₂ (1001)

C = 300 * 9.96

C =2988

Hence the capacity of the channel for teleprinter channel is 2988 bits per second.

8 0
4 years ago
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of 0.50 sec
GaryK [48]

Answer:

2.342m

Explanation:

Given

Time = 0.5 s

Height of Window = 2m

Because the pot was in view for a total of 0.5 seconds, we can assume that it took the cat 0.25 seconds to go from the bottom of the window to the top

Using this equation of motion

S = ut - ½gt²

Where s = 2

u = initial velocity = ?

t = 0.25

g = 9.8

So, we have.

2 = u * 0.25 - ½ * 9.8 * 0.25²

2 = 0.25u - 0.30625

2 + 0.30625 = 0.25u

2.30625 = 0.25u

u = 2.30625/0.25

u = 9.225 m/s ------------ the speed at the bottom of the pot

Using

v² = u² + 2gs to calculate the height above the window

Where v = final velocity = 0

u = 9.225

g = 9.8

S = height above the window

So, we have

0² = 9.225² - 2 * 9.8 * s

0 = 85.100625 - 19.6s

-85.100625 = -19.6s

S = -85.100625/19.6

S = 4.342

If 4.342m is the height above the window and the window is 2m high

Then 4.342 - 2 is the distance above the window

4.342 - 2 = 2.342m

6 0
3 years ago
Match each of the following terms to its definition:
Bingel [31]

I=B

II=C

III=E

IV=D

V=A

I have to write a bunch of extra things otherwise it won't let me post the answer lol.

7 0
3 years ago
Figure out what this says:<br><br> ?driew tib a kool ti seoD
lisov135 [29]

Answer:

Does it look a bit weird?

5 0
3 years ago
A technician is troubleshooting an employee laptop that has a wired network connectivity issue. The laptop can connect to the in
defon

By Tx/Rx reverse the technician can address this issue.

C. Tx/Rx reverse

<u>Explanation:</u>

Technician has to trouble the laptop, since the laptop is connected and got internet while is the network resources inside the office. But if he connects the same laptop in research lab end user is not connected

Following troubleshooting to made

1. Routing is done properly

2. Any packet dropping by using TRACE command in windows operating system.

Since DHCP is used in office, whereas same type is not used in research lab. End user can try TX/RX reverse cable to connect in the research laptop.

5 0
4 years ago
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