Answer:
public class ANot {
public static void main(String[] args) {
int numberOfSides = 20;
boolean isQuadrilateral;
if(numberOfSides==4){
isQuadrilateral = true;
System.out.println("The triangle is quadrilateral");
}
else{
isQuadrilateral=false;
System.out.println("The triangle is not quadrilateral");
}
}
}
Explanation:
- Create and Initilize the int variable numberOfSides (You can also receive this from a user using the scanner class for example).
- create a boolean variable isQuadrilateral
- Use if and else statement to check if numberOfSides ==4 and assign true to isQuadrilateral else assign false
Answer:
The "A" option is correct.
Explanation:
For CSS flexbox layout, the property "align-content" requires that the space in the flexbox is more than enough to show the items. In this case, to distribute evenly the items and show the first and last items aligned with the start and end of the main axis, the only suitable option is "space-between". This option leaves no space at the start or at the end of the flexbox, distributing the remaining space between the elements into the flexbox.
There is differen prices depending on the race go to the k1 website to see the packages
It gains purchasing power. Less money in circulation = more value.
Answer:
Net force = 20 N
Explanation:
Given that,
Force acting on the left = 10 N
Force acting on the right = 30 N
Let right side is positive and left side is negative. Let the net force acting on the box is F. So,
F = -10+30
F = 20 N
So, the net force on the box is 20 N and it is in right side.
