Find the zeros of the function p(x) = -9x^2 + 1

Mathematics

1 answer:

Musya8 [376]1 year ago

6 0

Step-by-step explanation:

zeroes = x intercept.

to find the x intercept we let y or in this case p(x) = 0

Hence,

-9x^2 + 1 = 0

-9x^2 = -1

x^2 = 1/9

x = 1/3

x = -1/3

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