Find the zeros of the function p(x) = -9x^2 + 1
1 answer:
Step-by-step explanation:
zeroes = x intercept.
to find the x intercept we let y or in this case p(x) = 0
Hence,
-9x^2 + 1 = 0
-9x^2 = -1
x^2 = 1/9
x = 1/3
x = -1/3
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