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MaRussiya [10]
2 years ago
10

Select the correct answer.

Mathematics
1 answer:
Serhud [2]2 years ago
7 0

Answer:

Dude

Step-by-step explanation:

There's nothing here

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If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5?A. 6B. 15C. 20D. 23
Marizza181 [45]

First, we will find the value of k

We can do this by sybstituting y=24, x=6 in;

y=kx and then solve for k

24= k(6)

divide both-side of the equation by 6

24/6 = k

4 = k

k=4

Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y

y= (4)(5)

y = 20

7 0
1 year ago
What is the equation of the line passing through (-2,-7) (4,23)
malfutka [58]

Answer:

The equation of line Passing through (2,3) and (4,7)

The slope of line is  

4−2

7−3

​  

=  

2

4

​  

=2

The equation of line is y−7=2(x−4)

y−7=2x−8

2x−y−1=0

Step-by-step explanation:

5 0
3 years ago
Heeeeeeelp pleeeease
Umnica [9.8K]

Answer:

<em>Solve for  b.  by simplifying both sides of the inequality, then isolating the variable.</em>

Inequality Form:

b < -\frac{3}{7}

Interval Notation:

( − ∞ , -\frac{3}{7} )

Hope this helps :)

<em>-ilovejiminssi♡</em>

8 0
3 years ago
Natalie was given a 30 question test. For each correct question she answered, she earned 2 points. For every incorrect answer sh
RideAnS [48]
T<span>he number of questions Natalie answered incorrectly.</span>
8 0
3 years ago
Y=x^2 -9x at x = 4 Find an equation of the tangent an an equation of the normal
Montano1993 [528]

The tangent line to <em>y</em> = <em>f(x)</em> at a point (<em>a</em>, <em>f(a)</em> ) has slope d<em>y</em>/d<em>x</em> at <em>x</em> = <em>a</em>. So first compute the derivative:

<em>y</em> = <em>x</em>² - 9<em>x</em>   →   d<em>y</em>/d<em>x</em> = 2<em>x</em> - 9

When <em>x</em> = 4, the function takes on a value of

<em>y</em> = 4² - 9•4 = -20

and the derivative is

d<em>y</em>/d<em>x</em> (4) = 2•4 - 9 = -1

Then use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-20) = -1 (<em>x</em> - 4)

<em>y</em> + 20 = -<em>x</em> + 4

<em>y</em> = -<em>x</em> - 24

The normal line is perpendicular to the tangent, so its slope is -1/(-1) = 1. It passes through the same point, so its equation is

<em>y</em> - (-20) = 1 (<em>x</em> - 4)

<em>y</em> + 20 = <em>x</em> - 4

<em>y</em> = <em>x</em> - 24

3 0
3 years ago
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