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kenny6666 [7]
3 years ago
9

Select all the expressions that are equivalent to -72/12

Mathematics
2 answers:
VLD [36.1K]3 years ago
4 0
The correct answers are B and C
kondor19780726 [428]3 years ago
3 0

Answer:

The correct answers are B and C

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The following graph a linear function, a nonlinear function, and/or a
Vikki [24]

Answer:

A

Step-by-step explanation:

It's linear function

As we can see the graph is a staright line.

so

  • y=f(x)

Every domain has unique range .

It's a relation also

6 0
2 years ago
–5y – 10 – 10y + –4y
EastWind [94]

Answer:

- 19y -10

Step-by-step explanation:

5 0
2 years ago
28 1/2 divided by 1/2
Alchen [17]

Answer: 57

Step-by-step explanation:

28 1/2 / 1/2

make 28 and 1/2 into 57/2

so now 57/2 divided by 1/2

the same as 57/2 times 2/1

multiply straight across

(57)(2)/(2)(1)

114/2

57

8 0
3 years ago
Read 2 more answers
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
Can someone please help me on number 19
Sloan [31]

Answer:

12\pi x^{2} +21\pi x+9\pi

Step-by-step explanation:

V=Bh=\pi r^{2} h = \pi (4x+3)^{2} (3x+3) = \pi (12x^{2}+12x+9x+9 )=12\pi x^{2} +21\pi x+9\pi

5 0
3 years ago
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