Algebra 2 help please

Mathematics

1 answer:

DaniilM [7]2 years ago

6 0

You multiply all the sides to find the value of x

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Math Help???????????

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Answer:

A,C,D,E

Step-by-step explanation:

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(X,Y) aka (horizontal, vertical)

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3 years ago

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The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

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Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$

Hence, the quotient is (x-2).

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How can you determine the equation that represents this relationship?

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How to do this help pleaseee

andreev551 [17]

Answer:

The answer to the equation should be -2

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