d = 3 , a₁₂ = 40 and S
= 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Answer:
Step-by-step explanation:
This is an arith. sequence.
The first term is 3 and the common difference is 1
Thus, the general formula for the nth term of this sequence is:
a(n) = 3 + 1(n - 1) This matches Answer A
The anser would be 500 with the exponet of 100 solve my multiplying
Answer:
58.8
Step-by-step explanation:
basic facts:
-15.4% is the same as 15.4/100
- the word 'of' in maths means times
so 15.4% of the 382ml is the same as
382*15.4/100
to do that, you multiply 382 by 15.4 = 5882.8
then you divide that by 100= 58.828
and then you just round that of to 58.8
