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olga55 [171]
3 years ago
6

Confusing confusion please help

Mathematics
2 answers:
Levart [38]3 years ago
8 0
Divide the shape into two parts, square triangle, the square is easy 2x2=4. The second part you know the length is 2 as 4-2=2, and because it is half of a square, it will be half of the area, so total answer is 6
White raven [17]3 years ago
5 0

Answer:

6

Step-by-step explanation:

Area = [(major base + minor base) x height]/2 = [(2+4)x2]/2 = 6

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Hello everyone, i am very confused by this question:
Lesechka [4]

Answer:

Read the explanation down

Step-by-step explanation:

This is a linear equation, because the equation does not have any exponents. Graph it by putting the equation into either slope-intercept form y=mx+b or point-slope form y−y1=m(x−x1).

Isolate y by first adding 6x to each side:

9y=6x−18

Divide each side by 9:

y=23x−2

Now graph the line y=23x−2 by first plotting the y intercept at (0,−2), then connecting points with a slope of 23.

graph{2/3x-2 [-10, 10, -5, 5]}

8 0
2 years ago
Measure the angle and classify it as right,acute, or obtuse
Jobisdone [24]

Answer: angle 2 is acute

Step-by-step explanation: the angle is less that 90⁰

7 0
3 years ago
Which expression is equivalent to -2 - 7?
SOVA2 [1]

Answer: -2 - (-7)

Step-by-step explanation: They both have the same outcome, 5. Which one is negative and one is positive. The last option is correct.

5 0
3 years ago
Read 2 more answers
Jimmy invests $7,000 in an account that pays 3% interest compounded semi-annually. What is his balance after 8 years?
Bumek [7]

Answer:

$8882.9

Step-by-step explanation:

A=p(1+(r/n))^nt

Given:P=7000, r=(3÷100%)=0.03 , n=2, t=8

A = 7000(1+(.03/2))^(2×8)

A = 7000 (1+0.015)^16

A = 7000 × 1.015^16

A = $8882.9

7 0
2 years ago
Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
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