The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.
Ways of having 17:
Die 1 Die 2 Die 3 sum
6 6 5 6+6+5 = 17
6 5 6 6+5+6 = 17
5 6 6 5+6+6 = 17
Those are the only 3 possibilities of having 17 (you can only loose 1 point).
The total number of outcomes are 6*6*6 = 216
So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139
The answer is 12t because i said so<span />
The three integers are x, x+2, x+4
5(3x+6)=42+x(x+2)
15x+30=x^2+2x+42
x^2 - 13x +12=0
(x-12)(x-1) = 0
x = 12 or 1
since the integers have to be odd we exclude 12
integers are 1,3,5
What is the topic? And formula to solve this?
Answer:
Interior angle
measures of any n-gon, where n represents the
number of sides of the polygon, by multiplying
(n - 2) 180°.
Hope this helps :D
