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3 years ago

2√18 - 2√12 + 2√18 = A) 6√2 - 4√3 B) 12√2 - 4√3 C) 6√2 D) 12√2

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

6 0

Answer:

Your answer is 12√2 - 4√3

Step-by-step explanation:

anyanavicka [17]3 years ago

3 0

Answer:

2√18 - 2√12 + 2√18 =

A) 6√2 - 4√3

<u> B) 12√2 - 4√3 </u>

C) 6√2

D) 12√2

Step-by-step explanation:

2sqrt18-2sqrt18=4sqrt18

4sqrt18-2sqrt12=

4sqrt18=12sqrt

2sqrt12=4sqrt3

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<h2>see below</h2>

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<h3>Question-6:</h3>

we are given a equation

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to solve so

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$\sf \displaystyle \: \log_{4}( - x \times (6 - x)) = 2$

simplify multiplication:

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remember $\displaystyle \log_{4}(4^2)=2$

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$\sf \displaystyle \: - 6 x + {x}^{2} = {4}^{2}$

simplify squares:

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move left hand side expression to right hand side and change its sign:

since we are moving left hand side expression to right hand side there'll be only 0 left in the left hand side

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$\sf \displaystyle \: {x}^{2} - 6x - 16 = 0$

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$\sf \displaystyle \: {x}^{2} + 2x - 8x - 16 = 0$

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$\sf \displaystyle \: x {(x}^{} + 2) - 8(x + 2) = 0$

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$\sf \displaystyle \: (x - 8){(x}^{} + 2) = 0$

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<h3>Question-7:</h3>

move left hand side log to right hand side:

$\displaystyle \: \log(x ) + \log(x - 21) = 2$

use mutilation logarithm rule;

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make it standard form:

$\displaystyle \: {x}^{2} - 21x - 100= 0$

factor:

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