<span>A hapten is one of Ruthie's symptoms that is an example of an innate defense mechanism. The hapten is a molecule which is small and it is not antigenic. The hapten also stimulates the process of production of antibodies in our own body.</span>
Answer:
Conclusion
Explanation:
When doing a science lab, the conclusion is the part at the end of the lab where you describe what you've learned and whether or not your hypothesis was supported by your results.
Answer:
d. multiple alleles and codominance
Explanation:
ABO blood group is controlled by three alleles instead of the usual two. Hence, it is an example of multiple alleles. These three alleles are IA, IB and i. IAIA genotype leads to production of A antigen hence A blood group. IBIB genotype leads to production of B antigen hence B blood group. When they are present together (IAIB) both A and B antigens are produced resulting in AB blood group. Hence ABO blood group is also an example of codominance.
Both IA and IB are dominant over the i allele. So IAi and IBi will produce A and B blood group respectively. ii genotype leads to O genotype.
Answer:
Transcription
Explanation:
Because for proteins synthesis to occur, the mRNA should be synthesized. This is wy the first step of protein synthesis is the transciption of mRNA from DNA.
Answer:
The answer is 50
Explanation:
Hemophilia is a X-linked disease. That means the recesive allele which causes the disease is not in Y chromosome, but only in X chromosome. If we denote:
X⁺ : dominant allele
X⁻: recesive allele
Then, in a woman there are three posibilities:
X⁺X⁻: is a carrier woman (without hemophilia)
X⁺X⁺: healthy woman
X⁻X⁻: woman with hemophilia
But in a man there are two posibilities:
X⁺Y: healthy man
X⁻Y: man with hemophilia
A man with hemophilia is X⁻Y, and a healthy woman whose mother had hemophilia is a carrier woman (X⁺X⁻). If they have a child, there are 4 posibilities, and each one has 1/4 of occurrence probability:
X⁻Y x X⁺X⁻ = X⁻X⁺, X⁻X⁻, X⁺Y, YX⁻
Posibilities with hemophilia are X⁻X⁻ and YX⁻ (1/4 + 1/4= 1/2= 0.5= 50%)
In each filial, there is a 50 percent of probability of having a child (man or woman) with hemophilia.
