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3 years ago

Cho ma trận hệ số chi phí trực tiếp ( về sản phẩm trung gian )dạng giá trị của 3 ngành năm t:

Mathematics

1 answer:

OleMash [197]3 years ago

4 0

Answer:

Step-by-step explanation:

sadasda

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Chris bought clothes for school. She bought 3 shirts for $12 each and a skirt for $15. How much money did Chris spend on her new

ollegr [7]

Answer:

Christ spent $51 on her new school clothes.

Step-by-step explanation:

12 * 3 = 36

36 + 15 = 51

3 0

3 years ago

Read 2 more answers

Martin has 28 basketball ball cards. Martin has 12 times as many basketball cards as Josie. Josie has 29 more cards than kal. Ho

Alona [7]

Answer:

28...?

Step-by-step explanation:

Well, the question states that Martin has 28 basketball cards at the start of the question, and asks how many he has at the end. Martin still has 28 cards. Unless part of the question was cut, then this is your answer.

7 0

3 years ago

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 m

bezimeni [28]

Answer: 0.75

Step-by-step explanation:

Given : Interval for uniform distribution : [0 minute, 5 minutes]

The probability density function will be :-

$f(x)=\dfrac{1}{5-0}=\dfrac{1}{5}=0.2\ \ ,\ 0$

The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-

$P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75$

Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75

7 0

3 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

3 years ago

The angles of a pentagon are x, x − 5 0 , x + 100 , 2x + 150and 2x + 300 . Find all the angles.

miv72 [106K]

Answer:

The interior angles are 70°,65°,80°,155° and 170°

Step-by-step explanation:

step 1

Find the sum of the interior angles of the pentagon

The sum is equal to

S=(n-2)*180°

where

n is the number of sides of polygon

n=5 (pentagon)

substitute

S=(5-2)*180°=540°

step 2

Find the value of x

Sum the given angles and equate to 540

x+(x-5)+(x+10)+(2x+15)+(2x+30)=540°

7x+50=540°

7x=490°

x=70°

step 3

Find all the angles

x=70°

(x-5)=(70-5)=65°

(x+10)=(70+10)=80°

(2x+15)=(2*70+15)=155°

(2x+30)=(2*70+30)=170°

8 0

3 years ago