Written numerically, the number you stated is written as:
5,004,300
Standard Form (Scientific Notation) numbers are written as a decimal (n.m) such that there is [normally] only one digit (n) to the left of the decimal point, and the rest of the number (m) to the right (with a possible limit). If there is only a single digit in the whole number then the value on the right is a zero (n.0).
To show that the value shown has shifted its decimal point position, the number of decimal positions shifted is shown after the number as a 10’s multiplied to the power of the number of positions shifted.
e.g., 102 = 102.0 = 1.02 (decimal point shifted left two places. If smallest digit is 0 then ignore it UNLESS it’s the ONLY digit!!)
1.02*10^2(2 Decimal shift to the left)
1.02*10^2
So, for the number asked in the question:
5,004,300 = 5,004,300.0
Left shift 6 times to largest digit = 5.004300
5.004300 (show the shift multiplier: 10^6)
5.004300*10^6
Step-by-step explanation:
According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B4%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B4%7D%CF%80%20%3D%20%5Cfrac%7B%CF%80%7D%7B2%7D)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.
I am joyous to assist you anytime.
The length of a rectangle is 4 meters longer than the width. if the area is 21 square meters, find the rectangle's dimensions. round to the nearest tenth of a meter.
let two integers be x and y
A.T.Q
x+y= -3
or, x= -3-y(i)
and xy= -18
or,(-3-y)y= -18[by(i)]
or,- -3y-y²= -18
or,-y²= -18+3
or, -y²= -15
or, y²=15
therefore y=✓15
from (i)
x= -3-✓15
y=√15
Step-by-step explanation:
I got you,
a) Work...
First equation: y = 4x + 3
Second equation: y = 2x + 11
If he wants to play 2 games...
y = 4 (2) + 3
y = 11
y = 2 (2) + 11
y = 15
<u>Answer for part a: If a customer wants to rent shoes and play two games, they'll pay more with the new price plan. With the current price plan, they'll pay 11 dollars, but with the new price plan, they'll pay 15 dollars.</u>
b) Work...
seven games...
y = 4 (7) + 3
y = 31
y = 2 (7) + 11
y = 25
<u>Answer for part b: If the customer wants to play 7 games, including the shoes, they would pay less using the new plan. If the shes were not included, the new price will still be less. With the shoes, 7 games, with the original plan, is 31 dollars but 25 dollars with the new plan. If they didn't want to rent shoes, they would pay 28 dollars with the original plan but only 14 dollars with the new plan. All in all, they spend less on the new plan anyways.</u>
I hope this helps :)
