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zlopas [31]
3 years ago
15

HELP DUE TODAYYYYYYYY

Mathematics
2 answers:
fomenos3 years ago
7 0

Answer:

Idc

Step-by-step explanation:

ira [324]3 years ago
3 0
Line one: y2-y1/x2-x1 which is -8-2/2-(-2) which equals -10/4 and as a decimal it’s -2.5
You might be interested in
What expression is equivalent to 1/3(4-5x-1)?
Serhud [2]
1/3( 4 - 5x - 1)


= (1/3)(4 +  - 5x +   - 1)

= (1/3)( 4)  + (1/3)(- 5x)  + (1/3)( - 1)

= 4/3 +  - 5x/3 +  - 1/3

=   - 5x/3  + 1  (Decimal:   - 1.666667x + 1)





Hope that helps!!!!
3 0
3 years ago
Read 2 more answers
Hakeem's frog made three quick jumps. The first was 1 meter. The second jump was 85 centimeters. The third jump was 400 millimet
anzhelika [568]
1 meter = 100 cm
85 cm
1 mm = 0.1 cm, so 400 mm = (400 x 0.1) = 40 cm

100 + 85 + 40 = 225 cm <== total length
3 0
3 years ago
Read 2 more answers
I NEED THIS ANSWERED ASAPPPPPP!!!!!!!!!!!!!1111 THANKS
Katyanochek1 [597]
The division is using extra zeros.
2 * 16  = 32, but 3200 was placed below 3426.

Now 1 * 16 = 16, so 160 goes below 226.
The number that goes in the box is 160.
8 0
3 years ago
GIVING BRAINLIESTTTTT
andreev551 [17]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

6 0
3 years ago
Between what two limits , expressed in degrees , are all acute angles found? All obtuse angles?
Tomtit [17]

Answer:

Acute angles are less than 90 degrees, obtuse angles are more than 90 degrees, and right angles are exactly 90 degrees.Step-by-step explanation:

4 0
3 years ago
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