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valentinak56 [21]
4 years ago
11

The probability of a spinner arrow stopping on green is 0.25. the probability of drawing a blue 3 from a pack of cards is 0.02.

The two events are independent. What is the approximate probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards?
Mathematics
1 answer:
Eddi Din [679]4 years ago
6 0
Be the event a spinner arrow stopping on green: A
The probability of a spinner arrow stopping on green: P(A)=0.25
Be the event drawing a blue 3 from a pack of cards: B
The propbability of drawing a blue 3 from a pack of cards: P(B)=0.02
The two events are independent
Probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards: P (A and B)=P(A <span>∩ B)=?

Since the events are independent:
</span>P(A ∩ B)=P(A)*P(B)
P(A ∩ B)=(0.25)*(0.02)
P(A ∩ B)=0.005

Answer: <span>The approximate probability of a spinner arrow stopping on a green and drawing a blue 3 from the pack of cards is 0.005</span>


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