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sergejj [24]
2 years ago
6

Find a number such that 20 less than twice the number is 50.

Mathematics
1 answer:
Inessa05 [86]2 years ago
7 0
140 because 70 (the half) minus 20 is 50
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Su has 3 times as many dolls as Bertha. When Su gives Bertha 4 dolls, they now have the same amount. How many dolls did they EAC
Usimov [2.4K]

Answer: i believe its 8

Step-by-step explanation:

i say 8 because 3x4 is 12 and so if bertha orignally had 4 and was given 4 she would have 8 and if su had 12 and gave away four she would also have 8

5 0
3 years ago
Read 2 more answers
In the transformation ABC A'B'C', the preimage of B' is ____. . a0
Misha Larkins [42]

Answer:

Pre image of B' is B

Step-by-step explanation:

Given:

ABC is a triangle

A transformation is done on ABC so that the image is A'B'C'.

Note that transformations are of various types such as dilation, vertical shift, horizontal shift, rotation about a point, reflection on a line, etc.

In any type of transformation, corresponding vertices will be matched.  In other words, A will become A', B will become B' and C will become C'.

Because of the property of the transformation to keep images similar and also transforming correspondingly the vertices we get preimage of B' would be nothing but B itself.

8 0
3 years ago
The bar graph below shows the student's favorite ice cream flavors. a) Use the graph's lines as a ruler to draw the intervals on
PtichkaEL [24]
Butter pecan: 25
Vanilla: 35
Chocolate: 50

The dotted line between 20 and 30 (butter pecan) will be nothing more than anything including 5. In this case, it is 25 counting up to 30.
The solid lines directly leading to a number will be that number, for instance, chocolate is 50.
3 0
3 years ago
Round 5.80405471744 to the nearest thousandth.
denis-greek [22]

Answer:

5.804

Step-by-step explanation:

5.804

  ^ ^ ^

After the thousands place is a 0, so the number for the thousands place would stay the same.  If it were higher than 4, it would round to 5.805 (but it isnt so it's 5.804)

tens, hundreds, thousands

4 0
3 years ago
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The sum of the first terms of an Arithmetic progression (Ap) is 130.if the fifth term is 3times,the first term,find the (a)commo
Nadusha1986 [10]

Answer:

For part a)

130 = 10/2[2a+(10-1)d]

Simplify, u get

2a + 9d = 26.................(1)

Also U5 = a + (5-1)d = 3a

Simplify, u get

a= 2d...................(2)

Substituting for a in equation 1,

2(2d)+9d= 26

Solving for d, we get

d = 2

In part b) substituting for d in equation 2 to get the first term

a = 2(2) = 4

Part c) the no. of terms required can be obtained by solving

28 = 4+(n-1)2

n = 13

5 0
3 years ago
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