Answer:
Correct Answer is C
since anything after x decides if it goes up or down like +7 goes up -7 goes down i don't know what would be if it goes sideways
Answer:
Step-by-step explanation:
A school has two computer labs and each lan has 30 computers. This means that the total number of computers is the sum of the number of computers in each lab
Total number of computers = 30+30 = 60
A total of six computers in the school or not working.
The expression that can be used to find the number of working computers in the school will be
Let the number of computers that are working be x
the number of computers that are working is total number of computers minus the number of computers that are not working be
The expression that can be used to find the number of working computers in the school will be
x = 60 - 6
x = 54
The trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ
<h3>
How to solve the trigonometric identity?</h3>
Since (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]
Using the identity a² - b² = (a + b)(a - b), we have
(cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]
= (cos²θ - sin²θ)(cos²θ + sin²θ)/[(1 - tan²θ)(1 + tan²θ)] =
= (cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] (since (cos²θ + sin²θ) = 1 and 1 + tan²θ = sec²θ)
Also, Using the identity a² - b² = (a + b)(a - b), we have
(cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] = (cosθ - sinθ)(cosθ + sinθ)/[(1 - tanθ)(1 + tanθ)sec²θ]
= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)/cosθ × (cosθ + sinθ)/cosθ × sec²θ]
= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)(cosθ + sinθ)/cos²θ × 1/cos²θ]
= (cosθ - sinθ)(cosθ + sinθ)cos⁴θ/[(cosθ - sinθ)(cosθ + sinθ)]
= 1 × cos⁴θ
= cos⁴θ
So, the trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ
Learn more about trigonometric identities here:
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Answer:
470,000
Step-by-step explanation:
since it is rounding, it would be to 470000.
Answer:
Stephon can buy total 4 chips bag and 2 candy bar
Step-by-step explanation:
Given as :
The money which Stephon has in his pocket = $ 12
The cost of one chips bag = $ 2.25
The cost of one candy bar = $ 1.50
The total number of items he can buy = 6
So, Let the number of chips bag he can buy = x
∴ The number of candy bar he can buy = 6 - x
Now, according to question
The number of chips bag×The cost of one chips bag + The number of candy bar×The cost of one candy bar = $ 12
Or, x × $ 2.25 + (6-x) × $ 1.50 = $ 12
Or, x × $ 2.25 + 9 - x × $ 1.50 = $ 12
or, x × $ 0.75 = 12 - 9
or, x = = 4
The number of chips bag he can buy = x = 4
And The number of candy bar he can buy = 6 - x = 6 - 4 = 2
Hence Stephon can buy total 4 chips bag and 2 candy bar . Answer