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3 years ago

9

DOES ANYONE KN0W THE ANSWER? Thankyou :)

1 answer:

IRINA_888 [86]3 years ago

5 0

Answer:

<em>Probability ⇒ 3 / 22</em>

Step-by-step explanation:

<em>~ Let us use this Venn Diagram to our benefit ~</em>

If 60 students are known to participate in both drama and sports, with 85 student in the drama club, and 200 in the sports teams;

Total Drama students ⇒ 85 students,

Drama students that are not in the sports teams ⇒ 85 - 60 = 25 students,

Total Sports Team students ⇒ 200 students,

Sports people not in Drama ⇒ 200 - 60 ⇒ 140 students

Now if there are a total of 330 students, we can find the students in neither club through such;

Total students in Drama and Sports ⇒ 85 + 200 = 285 students,

Students in Neither Drama nor Sports ⇒ 330 - 285 = 45 students,

<em>Students in Neither Drama nor Sports ⇒ 45 students</em>

This would mean the probability a students is neither in Drama nor Sports, is;

<em>Probability ⇒ 45 / 330 = 3 / 22</em>

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Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

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$y-2=1.5(x+2)$

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Part 2) we know that

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the product of their slopes is equal to minus one

so

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

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$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

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$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

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