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3 years ago

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A digital camera memory card is 1/4 full. The card is 2/3 full when 375 more pictures have been taken. How many pictures can the

memory card hold?

1 answer:

vlada-n [284]3 years ago

6 0

2/3 is roughly 67%
if you calculate 375/67% you would determine the max pictures the card could hold

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In Marissa's calculus course, attendance counts for 15% of the grade, quizzes count for 20% of the grade, exams count for

Alexandra [31]

Answer:

Her average was 87.35% on this course.

Step-by-step explanation:

In order to determine Marissa's average we need to take the average she has on each of the cattegories and find how much that relates to the weight of the cattegory on the final grade. We have:

Attendance counts for 15% of the grade and she has 100% average on that. So we have:

attendance = weight*(Marissa's average)

attendance = 15%*(100/100) = 15%

Quizzes counts for 20% of the grade and she has a 93% average on that. So we have:

Quizzes = weigth*(Marissa's average)

Quizzes = 20%*(93/100) = 18.6 %

Exams counts for 50% of the grade and she has a 82% average on that. So we have:

Exams = weigth*(Marissa's average)

Exams = 50%*(82/100) = 41%

The final exam counts for 15% of the grade and she has a average of 85% on that so we have:

Finals = 15%*(85/100) = 12.75%

So her grade is the sum of all the cattegories:

Course's average = 15+18.6+41+12.75 = 87.35 %

4 0

3 years ago

Read 2 more answers

annie adds 2 spoonfuls of sugar to her tea and sophie adds 3 spoonfuls to her tea. If one spoonful is 4 grams of sugar and a a c

Tresset [83]

240%

Step-by-step explanation:

if there is 240 grams then you just put a percent sing but are you asking What is the percentage of sugar in each cup? by spoons?

3 0

3 years ago

The values of 60, 62, and 84 were common to both samples. The three values are identified as outliers with respect to the age-gr

postnew [5]

Answer:

Only 60 is an identified outlier

Step-by-step explanation:

Given

<u>Age group: 40 to 50</u>

$Min = 60$ $Q_1 = 70$ $Median= 73$

$Q_3 = 76$ $Max = 85$

<u>Conditions for outlier</u>

$Value > Q_3 + 1.5 * IQR$

$Value < Q_1 - 1.5 * IQR$

<em>See attachment for complete question</em>

<u>Required</u>

Which of 60, 62 and 84 is an outlier of age grout 40 to 50 years

First, calculate the IQR of group 40 to 50.

This is calculated as:

$IQR = Q_3 - Q_1$

Where:

$Q_3 = 76$ and $Q_1 = 70$

So:

$IQR = 76 - 70$

$IQR = 6$

<em>Next, is to test the outlier conditions on each value (i.e. 60, 62 and 84)</em>

<u></u>

<u>Testing 60</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$60 > 76 + 1.5 * 6$

$60 > 76 + 9$

$60 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$60 < 70 - 1.5 * 6$

$60 < 70 - 9$

$60 < 61$ --- True

<em>Because one of the conditions is true, then 60 is an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 62</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$62> 76 + 1.5 * 6$

$62 > 76 + 9$

$62 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$62 < 70 - 1.5 * 6$

$62 < 70 - 9$

$62 < 61$ --- False

<em>Because both conditions are false, then 62 is not an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 84</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$84> 76 + 1.5 * 6$

$84 > 76 + 9$

$84 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$84 < 70 - 1.5 * 6$

$84 < 70 - 9$

$84 < 61$ --- False

<em>Because both conditions are false, then 84 is not an outlier of group 40 - 50 years</em>

5 0

3 years ago

Notacion cientifica 123000000

mihalych1998 [28]

Answer:

puro puto✌✌✌✌

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3 years ago

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HELP PLEASE ITS DUE TODAY!!!!!

Fofino [41]

Let's find.

$\\ \rm\Rrightarrow (-2x^3+x-5)(x^3-3x+4)$

$\\ \rm\Rrightarrow x^3(-2x^3+x-5)-3x(-2x^3+x-5)+4(-2x^3+x-5)$

$\\ \rm\Rrightarrow -2x^6+x^4-5x^3+6x^4-3x^2+15x-8x^3+4x-20$

$\\ \rm\Rrightarrow -2x^6+7x^4-13x^3-3x^2+19x-20$

#b

Yes

It's because multiplication law states that ab=ba

5 0

2 years ago