Ball hit the ground is when the function equals zero
0=-16t^2+46t+6
we can't factor so use quadraticformula
for
ax^2+bx+c=0
x=

x=

x=

x=

x=

x=

or

x=

or x=

x=-1/6 or x=3
we cannot have negative time because time starts at 0
disregard -1/6 as a possible answer
answer is after 3 seconds
Answer:
it would be close to 12 ft im not 100% sure though the measurements are a little off
Step-by-step explanation:
hypotenuse is 13
then you have the adjacent = 7
13^2 = 169
7^2= 49
169-49=120
the square root of 121 is 11 wich is fairly close to 120(doesnt have one because its not exact)
there is two extra feet so 11 +2 is 13 but there was a little less then 11 so i had sid roughly around 12
brainliest, please???
(3,2),(-9,6)
slope = (6 - 2) / (-9 - 3) = -4/12 = -1/3
y = mx + b
slope(m) = -1/3
use either of ur points...(3,2)....x = 3 and y = 2
now we sub into the formula and find b, the y int
2 = -1/3(3) + b
2 = -1 + b
2 + 1 = b
3 = b
so ur equation is : y = -1/3x + 3 <==
Answer:
u have the answer yet?
Step-by-step explanation:
?