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Scorpion4ik [409]
3 years ago
14

Given this quadratic equation, 2x^2-x-28=0,

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
4 0

\\ \sf\longmapsto 2x^2-x-28=0

\\ \sf\longmapsto 2x^2-8x+7x-28=0

\\ \sf\longmapsto 2x(x-4)+7(x-4)=0

\\ \sf\longmapsto (2x+7)(x-4)=0

\\ \sf\longmapsto x=7/2\:or\:x=4

Olegator [25]3 years ago
3 0

Step-by-step explanation:

how to help people that helps

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9/10 = z/8 round to the nearest tenth
jeka57 [31]
9/10 = z/8

cross multiply

9/10(10)(8) = z/8(8)(10)

9(8) = z(10)

72 = 10z

Isolate the z, divide 10 from both sides

72/10 = 10z/10

z = 72/10

z = 7.2

7.2, or D) is your answer

hope this helps
4 0
3 years ago
1/7 x 6 lol help pls
amm1812

Answer:

Hi there! the answer is: <u>0.857</u>

<u></u>

Step-by-step explanation:

1/7 x 6 = 0.85714285714 but you can ALWAYS shorten that for your answer by doing <u>0.857!</u>

<u></u>

Hope this helped! please mark me brainliest if possible

3 0
3 years ago
What is 171.76 divided by 555? Pls show work
vekshin1
171.76 ÷ 555 = 0.3094774775
8 0
3 years ago
1. Taylor needs to purchase a car. The car Taylor plans to purchase costs $10,000. Taylor has saved $2,000 to use as a down paym
Alexxandr [17]

Answer:

a. The amount Taylor will need to finance is $8,000

b. The amount Taylor pays as interest in one year is $400

Step-by-step explanation:

The given parameters of the financing for the car are;

The cost of the car Taylor plans to purchase, C = $10,000

The amount Taylor has saved to be used as down payment, S = $2,000

The interest rate of the credit Taylor is offered = 5%

The duration given for repayment of the loan = 5 years

a. To purchase the car, the amount Taylor will need to finance, 'P', is given as follows;

P = C - S

∴ P = $10,000 - $2,000 = $8,000

b. The amount of interest on the loan in one year, 'I', is given by the following formula;

I = \dfrac{P \times R \times T}{100}

Where;

I = The interest payed

P = The principal amount taken as loan = $8,000

R = The interest rate = 5% APR

T = The time period the interest is applied = 1 year

Plugging in the values, we get;

I = \dfrac{\$ \, 8,000 \times 5 \times 1}{100} = \$ \, 400

The interest Taylor will pay on the loan in one year, I = $4,00

7 0
3 years ago
Question 4 (1 point)
Zigmanuir [339]

Answer: 9

Step-by-step explanation:

plug in numbers to get 3+6

add them

boom

5 0
3 years ago
Read 2 more answers
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