Question

Given this quadratic equation, 2x^2-x-28=0,

Answer 1

$\\ \sf\longmapsto 2x^2-x-28=0$

$\\ \sf\longmapsto 2x^2-8x+7x-28=0$

$\\ \sf\longmapsto 2x(x-4)+7(x-4)=0$

$\\ \sf\longmapsto (2x+7)(x-4)=0$

$\\ \sf\longmapsto x=7/2\:or\:x=4$

Answer 2

Step-by-step explanation:

how to help people that helps