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kozerog [31]
2 years ago
15

Solve the system by elimination 3x-2y=3 15x-4y=-3

Mathematics
1 answer:
stiv31 [10]2 years ago
4 0

Answer:

x=-1

y=-3

Step-by-step explanation:

3x-2y=3(1)

5.(1) <=> 15x-10y=15 (2)

15x-4y=-3 (3)

(2)-(3) <=> -6y=18

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What is 50 minutes before 8:40 am
ale4655 [162]
7:50 am

60 minutes before 8:40 would be 7:40 so 10 minutes after that would be 7:50
3 0
3 years ago
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In the picture below, ABCD is a rectangle. If the area of triangle ABE is 40, what is the area of the triangle?
MariettaO [177]

Area of the rectangle: 112

Step-by-step explanation:

Picture is missing: find it in attachment.

The area of a triangle is given by

A=\frac{1}{2}bh

where

b is the length of the base

h is the height

For triangle ABE, we know that

A = 40 (area)

h = 8 (height)

So we can find the length of the base AE:

AE=b=\frac{2A}{h}=\frac{2(40)}{8}=10

Now we observe that the base of the rectangle, AD, is the sum of AE and DE, therefore:

AD=AE+DE=10+4=14

We also know the height of the rectangle AB is 8, and that the area of a rectangle is

A=bh

where b is the base and h the height. Therefore, the area of this rectangle is

A=bh=(AD)(AB)=(14)(8)=112

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brainly.com/question/4599754

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#LearnwithBrainly

7 0
3 years ago
If f'(0) = 5 and F(x) = f(3x), what is F'(0)?
Llana [10]

Answer:

\displaystyle F'(0) = 15

Step-by-step explanation:

We are given that:

f'(0) = 5 \text{ and } F(x) = f(3x)

And we want to find F'(0).

First, find F(x):

\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]

From the chain rule:

\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}

Then:

\displaystyle \begin{aligned} F'(0) & = 3f'(3(0)) \\ \\ & = 3f'(0) \\ \\ & = 3(5) \\ \\ & = 15\end{aligned}

In conclusion, F'(0) = 15.

7 0
2 years ago
Read 2 more answers
——————————————————————————————
DochEvi [55]
4. 3(3) + 2
(3 x 3) + 2 = 11
5. -(-6) -7
(+)6 -7 = -1
7 0
2 years ago
If x/0.5 + y/0.2 = 18, where x and y are positive integers, then what is the value of x ?
dem82 [27]
An equation without exponents and two variables, is typically a straight line. All the points on the line with integer coordinates are solutions of the equation. Since x and y have to be positive as well, there aren't that many solutions.

Let's see where the line crosses the x-axis, it is where y=0:

x/0.5 + 0 = 18, so x=9 at the intercept. y=0 there, so this is a point on the line, but not a solution to the question (y was supposed to be positive).

Possible values for x are thus limited to 1,2,3,4,5,6 and 7. You can try them all (ie., solve the equation with them) and see for which x values the y is also positive and integer.

You will find that x=4, y=2 is the only pair that satisfies these conditions.

7 0
2 years ago
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