7:50 am
60 minutes before 8:40 would be 7:40 so 10 minutes after that would be 7:50
Area of the rectangle: 112
Step-by-step explanation:
Picture is missing: find it in attachment.
The area of a triangle is given by

where
b is the length of the base
h is the height
For triangle ABE, we know that
A = 40 (area)
h = 8 (height)
So we can find the length of the base AE:

Now we observe that the base of the rectangle, AD, is the sum of AE and DE, therefore:

We also know the height of the rectangle AB is 8, and that the area of a rectangle is

where b is the base and h the height. Therefore, the area of this rectangle is

Learn more about area of figures:
brainly.com/question/4599754
brainly.com/question/3456442
brainly.com/question/6564657
#LearnwithBrainly
Answer:

Step-by-step explanation:
We are given that:

And we want to find F'(0).
First, find F(x):
![\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%20f%283x%29%5D)
From the chain rule:
![\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20F%27%28x%29%20%26%3D%20f%27%283x%29%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cleft%5B%203x%5Cright%5D%20%5C%5C%20%5C%5C%20%26%3D%203f%27%283x%29%5Cend%7Baligned%7D)
Then:

In conclusion, F'(0) = 15.
4. 3(3) + 2
(3 x 3) + 2 = 11
5. -(-6) -7
(+)6 -7 = -1
An equation without exponents and two variables, is typically a straight line. All the points on the line with integer coordinates are solutions of the equation. Since x and y have to be positive as well, there aren't that many solutions.
Let's see where the line crosses the x-axis, it is where y=0:
x/0.5 + 0 = 18, so x=9 at the intercept. y=0 there, so this is a point on the line, but not a solution to the question (y was supposed to be positive).
Possible values for x are thus limited to 1,2,3,4,5,6 and 7. You can try them all (ie., solve the equation with them) and see for which x values the y is also positive and integer.
You will find that x=4, y=2 is the only pair that satisfies these conditions.