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MAXImum [283]
3 years ago
15

It would be great if someone could help me with this problem

Mathematics
1 answer:
GaryK [48]3 years ago
7 0
Y-intercept (0, 1)
Equation of asymptote y=0

Equation of asymptote can also be called horizontal asymptote.
It means the place where the line almost meets but actually not touching the place. The line almost touches y=0 but it actually does not touch it.

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(Divide the following polynomials (x5 + y5) ÷ (x + y)
stiks02 [169]

\text{Use}\ a^5+b^5=(a + b) (a^4 - a^3 b + a^2 b^2 - a b^3 + b^4).\\\\(x^5+y^5):(x+y)=\dfrac{x^5+y^5}{x+y}=\dfrac{(x+y)(x^4-x^3y+x^2y^2-xy^3+y^4)}{x+y}\\\\=\boxed{x^4-x^3y+x^2y^2-xy^3+y^4}

7 0
3 years ago
Rolf spent 15 hours last week practicing his saxophone if 3/10 of the time was spent practicing warm up routines, how much time
NeTakaya
3/10 of the time = time spent on practicing warm up routines...
Time spent = 15 hours
remember that 'of' is usually multiply (x)
so ---- 3/10 x 15 =4.5 hrs

Hope this helps
3 0
3 years ago
Sandra has ribbons that are 2/6 meter 3/4meter and 4/9 meter long .She needs to use the ribbon longer than 2/3meter to make a bo
timurjin [86]

Answer:

3/4 meter

Step-by-step explanation:

Need Common denominators to compare size

2/6  3/4  4/9     which is longer than 2/3?

2/6 compared to 2/3.  2/6 = 2/6 and 2/3 = 4/6.  

2/6 < 2/3 so 2/6 is too short

3/4 compared to 2/3   3/4 = 9/12  and 2/3 =  8/12

3/4 > 2/3 so 3/4 is longer than 2/3

4/9 compared to 2/3  4/9 = 4/9 and 2/3 = 6/9

4/9 < 2/3 so 4/9 is too short

6 0
3 years ago
Read 2 more answers
PLEAS HELP!!! Examine the graph.
raketka [301]
Similarly to the last graph that decreased, this one increases, so you have to see where the line points upwards into the right top corner
CD
7 0
3 years ago
Read 2 more answers
If A+B= 45° then prove that: tanA+ tanB+ tanA. tanB​
Iteru [2.4K]

Answer:

See Explanation

Step-by-step explanation:

A+B= 45 \degree \\  \\ assuming  \:  \tan \: on \: both \: sides \\  \\\implies \: \tan( A+B)=  \tan 45 \degree \\  \\  \implies \: \tan( A+B)=  1 \:  \: \\  (  \because \: \tan 45 \degree = 1) \\  \\ \implies \:  \frac{\tan \: A +\tan \: B }{1 - \tan \: A .\tan \: B }  = 1 \\  \\ \implies \: \tan \: A +\tan \: B = 1 - \tan \: A .\tan \: B \\  \\ \purple{ \implies }\:  \orange{ \bold{\tan \: A +\tan \: B  + \tan \: A .\tan \: B= 1 }} \\  \\ thus \: proved

8 0
2 years ago
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