Answer: b. 37, 40, 41, 42
Explanation:
The next four octal numbers after 36 is 37, 40, 41, 42.
The octal numeral system, which is also referred to as "oct" for short, is simply base-8 number system.
It is a number system whereby only digits from 0 to 7 are used and there are no letters or numbers that are above 8 that are used.
In this case, after 36, the next number will be 37 after which we go to 40 as we can't write 38 in the octal system. Therefore, the next four octal numbers after 36 is 37, 40, 41, 42.
Answer:
20
Explanation:
assuming the print statement is not indented, the program effectively calculates 2+5+6+7.
The range(...) is <em>excluding </em>the end value (8 in this case).
Answer:
#include <stdio.h>
void interchangeCase(char phrase[],char c){
for(int i=0;phrase[i]!='\0';i++){
if(phrase[i]==c){
if(phrase[i]>='A' && phrase[i]<='Z')
phrase[i]+=32;
else
phrase[i]-=32;
}
}
}
int main(){
char c1[]="Eevee";
interchangeCase(c1,'e');
printf("%s\n",c1);
char c2[]="Eevee";
interchangeCase(c2,'E');
printf("%s\n",c2);
}
Explanation:
- Create a function called interchangeCase that takes the phrase and c as parameters.
- Run a for loop that runs until the end of phrase and check whether the selected character is found or not using an if statement.
- If the character is upper-case alphabet, change it to lower-case alphabet and otherwise do the vice versa.
- Inside the main function, test the program and display the results.
