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Romashka-Z-Leto [24]
3 years ago
10

The price of a car has been reduced from $15,000 to $9,000. What is the percentage decrease of the price of the car?

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

40<em>% is the decrease.</em>

<em />

Step-by-step explanation:

<em>To figure out the percentage decrease, you would first subtract the two numbers. </em>

<em />

<em />15000 - 9000 = 6000<em />

<em />

<em>Next, you would divide that number by the total.</em>

<em />

<em />6000 / 15000 = .4<em />

<em />

<em />15000 * .4 = 6000<em />

<em />

<em />15000 - 6000 = 9000<em />

<em />

<em />40<em>% </em><em>would be the decrease percentage. </em>

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A news item is spreading by word of mouth through a population of size 12,000 people. After t days, the number of people (in tho
Lilit [14]

Answer:

a) 2.303

b) f'(t)=\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}}

c) 1.3609

e) \frac{dy}{dx}=0.04y(12-y)

f)  4.5 thousand people(smaller)

7.5 thousand people (larger)

e) t=7.93 days (smaller)

t=10.06 days (larger)

g) 1.44

Step-by-step explanation:

The given function is y=f(t)=\frac{12}{1+75e^{-0.48t}}

To find how many thousand people have heard the news after 6 days, we substitute to get:

f(6)=\frac{12}{1+75e^{-0.48*6}}=2.303  thousands.

b) We rewrite to get: f(t)=12(1+75e^{-0.48t})^{-1}

We differentiate using the chain rule to obtain:

f'(t)=-12(1+75e^{-0.48t})^{-2}\cdot 75e^{-0.48t}\cdot -0.48

This simplifies to:

f'(t)=432e^{-0.48t}(1+75e^{-0.48t})^{-2}

We rewrite as positive index to get:

f'(t)=\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}}

c) To find the rate at which the news is spreading after 8 days, we substitute t=8 into f'(t)=\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}} to get:

f'(8)=\frac{432e^{-0.48\cdot 8}}{(1+75e^{-0.48\cdot 8})^{2}}=1.3609

d) The solution to the logistic differential equation:

\frac{dy}{dt}=ky(M-y)

is

y=\frac{M}{1+be^{-Mkt}}

By comparison, M=12, and Mk=0.48

12k=0.48\\k=0.04

The differential equation is:

\frac{dy}{dx}=0.04y(12-y)

e) To how many people have heard the news when its rate of spread is 1.35 thousand per day, we equate the differential equation to 1.35 and so for t first.

\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}}=1.35

This gives us: t=10.06 ot t=7.93

We substitute the times into the function to get:

f(7.93)=\frac{12}{1+75e^{-0.48\cdot7.93}}=4.5 thousand: smaller value

f(10.06)=\frac{12}{1+75e^{-0.48\cdot10.06}}=7.5 thousand: Larger value

f) The two times that the news is spreading at rate 1.35 thousand people per day are:

t=7.93 days: Smaller value

t=10.06: Larger value

g) To find the fastest rate at which the news spread we take the second derivative and equate it to zero.

f''(t)=0

This corresponds to where the horizontal line is tangent to

f'(t)=\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}}

From the graph the point of tangency is:

(8.99,1.44)

Therefore the fastest rate at which the news spread is 1.44

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Answer:

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Step-by-step explanation:

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Can someone explain, i'm literally sweating trying to figure it out
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Answer:

54 degrees.

Step-by-step explanation:

So a fun fact is that the exterior angle is equal to the sum of the opposite two interior angles (at least within triangles).

Given this, set these values equal to each other to get the value of a.

d = a + b

2a = (a+10)+44

2a = a + 54

a = 54

The measure of the exterior angle is 54 degrees.

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