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2 years ago

Cho ma trận A và một sự tương ứng

Mathematics

1 answer:

algol [13]2 years ago

4 0

Answer:

sorry I don't speak that language

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Can you help me solve x-1<-1 or 8x+9≥41

Elza [17]

For the first one:
x-1<-1
Add one on both sides.
x<0

For the second one:
8x+9≥41
Subtract nine on both sides.
8x+≥32
Divide by eight on both sides.
x≥4

HOPE THIS HELPS YOU! ^_^

3 0

3 years ago

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Help me I’m not sure how to do this

maw [93]

Answer:

_______

Step-by-step explanation:

i cant read that sorry :|

6 0

2 years ago

Determine the midpoint between the two points x(4,-6) and y(-2,8)

ikadub [295]

Answer:

$p(a, b) = (1, 1)$

Step-by-step explanation:

Midpoint formula is

$p(a, b)=(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )$ ---------------(1)

Here

$(x_1, y_1) = (4, -6) \ \ \ and \ \ \ (x_2, y_2) = (-2, 8)$

Substituting values in equation (1)

$p(a, b)=(\frac{4 - 2}{2}, \frac{-6 + 8}{2} )$

$p(a, b) = (1, 1)$

6 0

3 years ago

The coordinates of the endpoint of QS are Q(-9,8) and S(9,-4). Point R is on cue as such that QR:RS Is in the ratio 1:2. What ar

marishachu [46]

R(–3, 4)

Step-by-step explanation:

Let Q(-9,8) and S(9,-4) be the given points and let R(x, y) divides QS in the ratio 1:2.

By section formula,

$R(x, y)=R\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)$

Here, $x_{1}=-9, y_{1}=8, \text { and } x_{2}=9, y_{2}=-4 \text { and } m=1, n=2$

Substituting this in the section formula

$R(x, y)=R\left(\frac{1(9)+2(-9)}{1+2}, \frac{1(-4)+2(8)}{1+2}\right)$

To simplifying the expression, we get

$\Rightarrow R(x, y)=R\left(\frac{9-18}{3}, \frac{-4+16}{3}\right)$

$\Rightarrow R(x, y)=R\left(\frac{-9}{3}, \frac{12}{3}\right)$

⇒ R(x,y) = R(–3,4)

Hence, the coordinates of point R is (–3, 4).

6 0

3 years ago

Tell whether (1,6) is a solution of y = x + 7

andrezito [222]

Answer:

no it is not a solution.READ THE WHOLE EXPLANATION! IT WILL HELP WITH THE OTHER PROBLEMS!!!!

Step-by-step explanation:

when something like (1,6) is written consider it as (x,y). in this case, 1 is considered as x, and 6 is considered as y. if you substitute these number for x and x and y, (x =1 and y =6), you'll see that the equation will go from y=x +7, to 6=1+7. Which is not true.

5 0

3 years ago

Read 2 more answers