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Arte-miy333 [17]
3 years ago
5

if you are graphing a system of equations, but the graph doesn't give you enough space to plot the y intercept or slope, what do

you do? HELP ASAP
Mathematics
1 answer:
Marysya12 [62]3 years ago
3 0
I’ve been there and I think it most likely means that you’re plotting it wrong. The graph should always have space for you to graph the problem correctly.
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Which function is equivalent to the inverse of y=sec(x)
kipiarov [429]
From the identity:

sec(x)= \frac{1}{cos(x)}


f(x)=sec(x)= \frac{1}{cos(x)}

the inverse of f is g such that f(g(x))=x,

we must find g(x), such that \frac{1}{cos[g(x)]}=x

thus, cos[g(x)]= \frac{1}{x}

g(x)=cos^{-1} (\frac{1}{x})


Answer: b. g(x)=cos^-1(1/x)   
6 0
4 years ago
If the gradient of a line, A, is 4, what is the gradient of a line which is perpendicular to A?
Ne4ueva [31]

Answer:

m = - 1/4

Step-by-step explanation:

When two line is perpendicular to each other the product of them is - 1

So let the other line be B

Gradient of B = t

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therefore m = - 1/4

8 0
2 years ago
Help me, cause I'm tuck
r-ruslan [8.4K]

Answer:

The answer would be 1.33 x 10^{4}

Step-by-step

1.28 x 10^{4} = 12800

5 x 10^{2} = 500

12800 + 500 = 13300

13300 = 1.33 x 10^{4} in scientific notation

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8 0
4 years ago
Graph -5x-8y=40
Triss [41]

Answer:

Please, see the attached file.

Thanks.

Step-by-step explanation:

-5x-8y=40

This is a linear equation, and its graph is a right line, we only need two points, because by two points only goes trough only a right line:

1) For x=0→ -5(0)-8y=40

0-8y=40

-8y=40

Dividing both sides of the equation by -8:

-8y/(-8)=40/(-8)

y=-5

Point=(x,y)→Point=(0,-5)


2) For y=0→ -5x-8(0)=40

-5x-0=40

-5x=40

Dividing both sides of the equation by -5:

-5x/(-5)=40/(-5)

x=-8

Point=(x,y)→Point=(-8,0)


With these two points (0,-5) and (-8,0) we can draw the right line.



8 0
4 years ago
3/4 divided by 4/5 is 15/16 is it in its lowest terms​
Softa [21]

Answer:

yes it cant be siplified anymore

Step-by-step explanation:

8 0
3 years ago
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