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Hunter-Best [27]
3 years ago
6

What is a slope perpendicular to the line with equation 6x-4y=30. Can u guys show me step by step. (I’m barely learning and I’m

confused)

Mathematics
2 answers:
Amanda [17]3 years ago
7 0
There is the work to solve.

Anastasy [175]3 years ago
5 0
I did these about 1 year ago but i think you subtract the 6 from 30 and then divide by 4, and that gives u 24/4 which is 6. i barely barely remember some so
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Saturn is about 10 times as far as earth from the sun
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Which transformations would affect the asymptote of a logarithmic<br> function?
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Transformations of logarithmic graphs behave similarly to those of other parent functions. We can shift, stretch,compress, and reflect the parent function y=log b (x) without loss of shape.
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A line passes through the points (-4,5) and (1,-5). Write the equation of the line in slope-
sweet [91]

Answer:

y = -2x - 3

Step-by-step explanation:

Slope: (5 - - 5)/(-4 -1) = 10/-5 = -2

y-intercept: 5 - (-2)(-4) = -3

4 0
3 years ago
Which second-degree polynomial function has a leading coefficient of –1 and root 5 with multiplicity 2?
PIT_PIT [208]
A second degree polynomial function has the general form:

                  \displaystyle{f(x)=ax^2+bx+c, where a\neq0.

The leading coefficient is a, so we have a=-1.

5 is a double root means that :

i) f(5)=0,
ii) the discriminant D is 0, where D=b^2-4ac.

Substituting x=5, we have

                                        f(5)=a(5)^2+b(5)+c,

and since f(5)=0, and a is -1 we have:

                                          0=-25+5b+c
thus c=25-5b.


By ii) \displaystyle{b^2-4ac=0.

Substituting a with -1 and c with 25-5b we have:
                                     
          \displaystyle{b^2-4ac=0
          \displaystyle{b^2-4(-1)(25-5b)=0
          \displaystyle{b^2+4(25-5b)=0
          \displaystyle{b^2-20b+100=0
          \displaystyle{(b-10)^2=0
          \displaystyle{b=10 


Finally we find c: c=25-5b=25-50=-25

Thus the function is        \displaystyle{f(x)=-x^2+10x-25


Remark: It is also possible to solve the problem by considering the form

f(x)=-1(x-5)^2 directly.

In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is f(x)=a(x-r)^2
5 0
3 years ago
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What values of x make the equation x2 + 9x – 22 = 0 true? Check all that apply. –11 –2 0 2 11
Marat540 [252]
Answer:  x = 2 ;  -11 .
___________________________________
Explanation:
_____________________________________________
Given the equation:
_____________________________________________
  x² + 9x −<span> 22 = 0  ;  Solve for:  "x" ;
_____________________________________________

Let us factor the "left-hand side" of the equation:
_____________________________________________
  "x</span>² + 9x −<span> 22"  ;
_____________________________________________

What are the factors of "-22"" that add up to "positive 9" ?
_____________________________________________
  Let us list the factors of "-22" :
____________________________________________
-2, 11;  </span>→ -2 + 11 = 9 ;<span>
-11, 2;  </span>→ -11 + 2 = -9 ;<span>
____________________________________________

So we have:  "-2" and "11" ;
____________________________________________
So;   </span>  "x² + 9x − 22" ; factors into " (x−2)(x + 11)" ;
____________________________________________
We have:  (x−2)(x + 11) = 0 ;

So:  x − 2 = 0 ;  

Add "2" to each side of the equation; 

     x − 2 + 2 = 0 + 2 ; 

          x = 2 ; 
___________________________________
   x + 11 = 0 ;

Subtract "11" from each side of the equation;

   x + 11 − 11 = 0 − 11 ;

      x = -11 ; 
___________________________________
 Answer:  x = 2 ; -11 .
___________________________________
6 0
3 years ago
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